#Today's question: Question no.3

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  1. Isolobal analogy:-
    [Fe(Co)2 (PPh3)] - Valence electrons=8+4+2+1=15 electrons.
    18-15=3 holes.
    (a) CH2+=4+2-1=5
    8-5=3 holes.
    Ans:- CH2+

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  2. [Fe(co)2(pph3)-
    valence electron for fe-8 , co-4 ,pph3 -2
    Negative charge have +1
    Holes are calculated by 8+4+2+1=15e-
    Orbital completely filled by 18 electron
    So 18-15=3HOLES

    In CH2+
    C-4
    H-2
    Positive charge have -1
    So 4+2-1=5
    Orbital completely filled by 8 electron so 8-5=3hole
    The answer is CH2+

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  3. Valence electron 8+4+2+1=15
    Orbital completely filled by 18
    18-15=3 holes
    CH2+
    4+2-1=5
    8-5=3holes
    Answer:a)CH2+

    ReplyDelete
  4. (Fe(CO)2(PPh3))8+4+2+1=15e-
    Completely filled is 18 electrons
    18-15=3 holes
    Completely filled 8 electrons
    In CH2+=4+2-1=5
    8-5=3 holes
    So answer is CH2+

    ReplyDelete
  5. (Fe(co) 2(pph3))
    Valence electron
    Fe-8
    Co-2(2*2=4)
    Pph3-2
    Negative charge have +1
    8+4+2+1=15
    18-15=3holes
    CH2+
    4+2-1=3holes
    Ans CH2+

    ReplyDelete

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