[Fe(co)2(pph3)- valence electron for fe-8 , co-4 ,pph3 -2 Negative charge have +1 Holes are calculated by 8+4+2+1=15e- Orbital completely filled by 18 electron So 18-15=3HOLES
In CH2+ C-4 H-2 Positive charge have -1 So 4+2-1=5 Orbital completely filled by 8 electron so 8-5=3hole The answer is CH2+
(Fe(CO)2(PPh3))8+4+2+1=15e- Completely filled is 18 electrons 18-15=3 holes Completely filled 8 electrons In CH2+=4+2-1=5 8-5=3 holes So answer is CH2+
Isolobal analogy:-
ReplyDelete[Fe(Co)2 (PPh3)] - Valence electrons=8+4+2+1=15 electrons.
18-15=3 holes.
(a) CH2+=4+2-1=5
8-5=3 holes.
Ans:- CH2+
[Fe(co)2(pph3)-
ReplyDeletevalence electron for fe-8 , co-4 ,pph3 -2
Negative charge have +1
Holes are calculated by 8+4+2+1=15e-
Orbital completely filled by 18 electron
So 18-15=3HOLES
In CH2+
C-4
H-2
Positive charge have -1
So 4+2-1=5
Orbital completely filled by 8 electron so 8-5=3hole
The answer is CH2+
Valence electron 8+4+2+1=15
ReplyDeleteOrbital completely filled by 18
18-15=3 holes
CH2+
4+2-1=5
8-5=3holes
Answer:a)CH2+
(Fe(CO)2(PPh3))8+4+2+1=15e-
ReplyDeleteCompletely filled is 18 electrons
18-15=3 holes
Completely filled 8 electrons
In CH2+=4+2-1=5
8-5=3 holes
So answer is CH2+
(Fe(co) 2(pph3))
ReplyDeleteValence electron
Fe-8
Co-2(2*2=4)
Pph3-2
Negative charge have +1
8+4+2+1=15
18-15=3holes
CH2+
4+2-1=3holes
Ans CH2+